Rex Kerr
1 min readNov 1, 2022

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I'm being silly while poking fun at Chalmers! It's not an actual argument. I do appreciate the actual argumentation you supplied.

Regarding round squares, a circle is the roundest thing there is, and a circle of diameter d consists of all points a distance no greater than d/2 from the center. In contrast, a square of side d consists of all points within +- d/2 in every dimension.

In two dimensions, if we place our shapes at (0, 0) then our circle is all points x, y such that x^2 + y^2 <= r^2. The square is all points x, y such that -r <= x <= r and -r <= y <= r.

But in one dimension, we don't have any y. So it's just x^2 <= r^2 and -r <= x <= r, which is the exact same statement. So, we have a perfectly round square, in 1D.

(Interestingly, in high dimensions the corners of squares get sharper and sharper until the thing feels like a porcupine, while circles stay perfectly round. 10000-dimensional squares are incredibly not-round, which has important implications for machine learning and the like.)

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Rex Kerr
Rex Kerr

Written by Rex Kerr

One who rejoices when everything is made as simple as possible, but no simpler. Sayer of things that may be wrong, but not so bad that they're not even wrong.

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